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1952 United States presidential election in Iowa

The 1952 United States presidential election in Iowa took place on November 4, 1952, as part of the 1952 United States presidential election. Iowa voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[3]

United States presidential election in Iowa, 1952

← 1948 November 4, 1952[1] 1956 →

All 10 Iowa votes to the Electoral College
  General of the Army Dwight D. Eisenhower 1947.jpg AdlaiEStevenson1900-1965.jpg
Nominee Dwight D. Eisenhower Adlai Stevenson
Party Republican Democratic
Home state New York[2] Illinois
Running mate Richard Nixon John Sparkman
Electoral vote 10 0
Popular vote 808,906 451,513
Percentage 63.75% 35.59%

President before election

Harry S. Truman

Elected President

Dwight D. Eisenhower

Iowa was won by Columbia University President Dwight D. Eisenhower (RNew York), running with Senator Richard Nixon, with 63.75% of the popular vote, against Adlai Stevenson (DIllinois), running with Senator John Sparkman, with 35.59% of the popular vote.


United States presidential election in Iowa, 1952[3]
Party Candidate Votes %
Republican Dwight D. Eisenhower 808,906 63.75%
Democratic Adlai Stevenson 451,513 35.59%
Progressive Vincent Hallinan 5,085 0.40%
Prohibition Stuart Hamblen 2,882 0.23%
Socialist Workers Darlington Hoopes 219 0.02%
Socialist Labor Eric Hass 139 0.01%
Write-ins Write-ins 29 0.00%
Total votes 1,268,773 100%


  1. ^ "United States Presidential election of 1952 - Encyclopædia Britannica". Retrieved July 25, 2017.
  2. ^ "U.S. presidential election, 1952". Facts on File. Retrieved October 24, 2013. Eisenhower, born in Texas, considered a resident of New York, and headquartered at the time in Paris, finally decided to run for the Republican nomination
  3. ^ a b "1952 Presidential Election Results Iowa".