1916 United States presidential election in Iowa(Redirected from United States presidential election in Iowa, 1916)
The 1916 United States presidential election in Iowa took place on November 7, 1916, as part of the 1916 United States Presidential Election which was held throughout all contemporary 48 states. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.
Iowa was won by Republican nominee, U.S. Supreme Court Justice Charles Evans Hughes of New York, and his running mate Senator Charles W. Fairbanks of Indiana. They defeated Democratic nominees, incumbent Democratic President Woodrow Wilson and Vice President Thomas R. Marshall.
Hughes won the state by a margin of 11.36 percent.
|United States presidential election in Iowa, 1916|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||Charles Evans Hughes of New York||Charles Warren Fairbanks of Indiana||280,439||54.25%||13||100.00%|
|Democratic||Woodrow Wilson of New Jersey||Thomas Riley Marshall of Indiana||221,699||42.89%||0||0.00%|
|Socialist||Allan Louis Benson of New York||George Ross Kirkpatrick of New Jersey||10,976||2.12%||0||0.00%|
|Prohibition||James Franklin Hanly of Indiana||Ira Landrith of Tennessee||3,371||0.65%||0||0.00%|
|Socialist Labor||Arthur E. Reimer of Massachusetts||Caleb Harrison of Illinois||459||0.09%||0||0.00%|
- "1916 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1916 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 23 December 2013.