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1912 United States presidential election in Nebraska

The 1912 United States presidential election in Nebraska took place on November 5, 1912, as part of the 1912 United States presidential election. Nebraska voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Nebraska, 1912

← 1908 November 5, 1912 1916 →
  Woodrow Wilson-H&E.jpg Theodore Roosevelt-Pach.jpg William Howard Taft - Harris and Ewing.jpg
Nominee Woodrow Wilson Theodore Roosevelt William Howard Taft
Party Democratic Progressive Republican
Home state New Jersey New York Ohio
Running mate Thomas R. Marshall Hiram Johnson Nicholas M. Butler
(replacing James S. Sherman)
Electoral vote 8 0 0
Popular vote 109,008 72,681 54,226
Percentage 43.69% 29.13% 21.74%

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

Nebraska was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 43.69% of the popular vote, against the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 29.13% of the popular vote and the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 21.74% of the popular vote.[1]

ResultsEdit

United States presidential election in Nebraska, 1912[1]
Party Candidate Votes %
Democratic Woodrow Wilson 109,008 43.69%
Progressive Theodore Roosevelt 72,681 29.13%
Republican William Howard Taft 54,226 21.74%
Socialist Eugene V. Debs 10,185 4.08%
Prohibition Stuart Hamblen 3,383 1.36%
Total votes 243,776 100%

ReferencesEdit

  1. ^ a b "1912 Presidential Election Results Nebraska".