Jnana theertha
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Dark matter's full information
Let take the dark matter size in mass and then we can convert into energy Finding the mass of dark matter m=F/a
By using universal law of gravity we can convert gravitational force value to force by using its SI units of gravitational, radius and masses . The gravitational force value is G = 6.673 × 10-11 Nm^2 kg^-2 Let us round off it to G= 6.7 × 10^-11 Nm^2 kg^-2 Universal law of gravity formula F = G(m1×m2)/R^2 The SI unit of masses is kg and the radius is metre and the gravitational SI unit are Nm^2 and kg^-2 So
F= 6.7 × 10^-11 Nm^2 kg^-2(kg1×kg2)/m^2 F=6.7 × 10^-11N The speed of the dark matter is 54 m/sec Finding acceleration through speed A= dS/dT =54/1 =54m/sec^2 By using formula m=F/a m=6.7×10^-11/54 m=1.24074074e-12 kg
Converting acceleration to velocity v=a×t =54×1 54m/sec Converting mass and velocity into kinetic energy K.E=1/2 mv^2 1/2×1.24074074 e-12×54×54 1.809 e-9J Converting the kinetic energy into electron volts 1J=6.242×10^18ev =6.242×10^-18×1.809×10^-9 =1.129089×10^10ev The mass of the dark matter particle is 1.129089×10^10ev
The creation of dark matter theory
Proof for the theory is
By putting black paint more and yellow paint less to the water you can observe dark matter let water be the gravitational force and black paint be the dark matter. when you put the yellow paint it will disappears this shows that dark matter does not interact with any other matter. Gravitons which carries the gravitational force played the major role in creation of dark matter particle. We know that gravitons played major role in creation of dark matter. Let us find the radius from the Mass velocity and force r=mv^2/F =1.240×10^-12×54^2/6.7×10^-11 r=5.396×10^-21m The radius of the dark matter particle is 5.396×10^-21m The shape of the dark matter is sphere Our whole universe is in sphere and the volume is calculated by sphere formula. From this we can obtain that dark matter shape is sphere This is the proof for this that dark matter is in the sphere shape
The shape of the dark matter is sphere so The volume formula to find the volume of the sphere is and the radius of the dark matter is 5.396×10^-21m V = 4/3 π r³
=4/3×π×(5.396×10^-21)^3 =6.58383897×10^-61m^3
The volume of the dark matter particle is 6.58383897×10^-61 m^3 To obtain pressure of dark matter we want energy density. Kinetic energy is a form of energy so let us Converting kinetic energy and volume to energy density Energy density =energy (kinetic energy)/volume =1.809×10^-9/6.58383897×10^-61 =2.74763707×10^-71 J/m^3 The energy density of dark matter particle is 2.74763707×10^-71 J/m^3 Let's find the dark matter pressure through energy density The pressure finding formula from energy density is P=2/3E
=2/3×2.74763707×10^-71 =1.83175805×10^-71 Pascal
The pressure of dark matter particle is 1.83175805×10^-71 Pascal Finding the density of dark matter through volume and mass density = mass / volume.
=1.240×10^-12/6.58383897×10^-61
=1.8833996×10^-74 kg/m^3 The density of the dark matter particle is 1.8833996×10^-74 kg/m^3 information about gravitons Let us find the mass of the gravitons through Newton's second law m=F/a By using universal law of gravity we can convert gravitational force value to force by using its SI units of gravitational, radius and masses . The gravitational force value is G = 6.673 × 10-11 Nm^2 kg^-2 Let us round off it to G= 6.7 × 10^-11 Nm^2 kg^-2 Universal law of gravity formula F = G(m1×m2)/R^2 The SI unit of masses is kg and the radius is metre and the gravitational SI unit are Nm^2 and kg^-2 So
F= 6.7 × 10^-11 Nm^2 kg^-2(kg1×kg2)/m^2 F=6.7 × 10^-11N The speed of graviton is 4,586,509.7447 m/s Let us convert the speed into acceleration A= dS/dT
= 4,586,509.7447/1
=4,586,509.7447
Let us find the mass of graviton
m=F/a
m=6.7×10^-11/4,586,509.7447
=1.46080579×10^-17 kg
The mass of the graviton is 1.46080579×10^-17 kg Let us convert acceleration to velocity to obtain kinetic energy v=a×t
=4,586,509.7447/1 =4,586,509.7447
Let us obtain in kinetic energy through velocity and mass K.E=1/2 mv^2 =1/2×1.460×10^-17×4,586,509.7447^2 =0.000307126646J Let us convert kinetic energy into elctron volt to obtain electrons of graviton 1J=6.242×10^18ev
=6.242×10^18×0.000307126646 =1.916 932 915 284 7×10^15ev
The mass of the graviton is 1.916 932 915 284 7×10^15ev Let prove the existence of gravitons through Quantum mechanics laws 1Wave particle duality The formula for save particle duality is λ = h/p Let's find the momentum through velocity and mass p=m×v =1.460×10^-17×4,586,509.7447 =6.69630423×10^-11 kgm/sec Let find wave particle duality λ = h/p.
=6.63×10^-34/6.69630423×10^-11 =9.90098384×10^-46 m
Wave particle duality of graviton is 9.90098384×10^-46 m 2.Quantization Finding frequency through speed and wave length to obtain energy f = 𝜈/λ
=4,586,509.7447/9.90098384×10^-46
=4.63237777×10^-41 Hz Let's obtain the energy through planck constant and frequency to get Quantum number of electron E=hf =6.63×10^-34×4.63237777×10^-41 =3.07126646×10^-74 J The quantized energy of the graviton is 3.07126646×10^-74 J Let s find the Quantum number of gravitons through energy, frequency and planck constant E=(n+1/2)hf 3.07126646×10^-74=(n+1/2)6.63×10^-34×4.63237777×10^-41 n=0.5 The Quantum number of gravitons is 0.5 ∆x=λ ∆x=λ= =9.90098384×10^-46 m ∆x =9.90098384×10^-46 m The uncertainty position of the graviton is9.90098384×10^-46 m 4.Conservation law Conservation law of energy is applicable for the gravitons because the gravitational waves can neither be created nor be destroyed. Let us find the radius from the Mass velocity and force r=mv^2/F =1.46080579×10^-17×4,586,509.7447^2/6.7 × 10^-11 =4.5865097×10^-16 m The radius of the graviton is 4.5865097×10^-16 m Through I have proved existence of gravitons through Quantum mechanics laws
Your submission at Articles for creation: Dark matter's full information and Information about the gravitons (August 4)
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Hello, Jnana theertha!
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Your submission at Articles for creation
edit - If you would like to continue working on the submission, go to the submission and click on the "Edit" tab at the top of the window.
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I have proved it scientifically and accurately what are the reasons to decline this article please accept the article and please publish it
Your submission at Articles for creation: Riemann hypothesis information (September 8)
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