1860 United States presidential election in New York
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The 1860 United States presidential election in New York took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose 35 electors of the Electoral College, who voted for president and vice president.
|Turnout||95.5% 5.6 pp|
Lincoln won the Empire State by a margin of 7.42%.
|1860 United States presidential election in New York|
|Fusion[a]||Stephen A. Douglas / John Bell / John C. Breckinridge||312,510||46.29%||0|
- The slate of electors were pledged to 3 different candidates: 18 to Douglas, 10 to Bell, and 7 to Breckinridge.
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1860 Presidential General Election Results - New York". U.S. Election Atlas. Retrieved 3 August 2012.
- Dubin, Michael J., United States Presidential Elections, 1788–1860: The Official Results by County and State, McFarland & Company, 2002, p. 187
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