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1976 United States presidential election in North Dakota

  (Redirected from United States presidential election in North Dakota, 1976)

The 1976 United States presidential election in North Dakota took place on November 2, 1976, as part of the 1976 United States presidential election. North Dakota voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in North Dakota, 1976

← 1972 November 2, 1976 1980 →
  Gerald Ford, official Presidential photo.jpg Carter cropped.jpg
Nominee Gerald Ford Jimmy Carter
Party Republican Democratic
Home state Michigan Georgia
Running mate Bob Dole Walter Mondale
Electoral vote 3 0
Popular vote 153,470 136,078
Percentage 51.7% 45.8%

President before election

Gerald Ford

Elected President

Jimmy Carter

North Dakota was won by the Republican candidate and incumbent President, Gerald Ford, with 51.66% of the popular vote, against the Democratic candidate, Jimmy Carter, with 45.80% of the popular vote.[1] American Party candidate Thomas Anderson finished highest among third parties; finishing with 1.24% of North Dakota's popular vote.

Despite losing in North Dakota, Carter went on to win the national election and became the 39th president of the United States.[2] As of the 2016 presidential election, this is the last election in which Morton County, Walsh County, McLean County, Pierce County, Cavalier County, Emmons County, Dunn County, Foster County, Renville County, Griggs County, and Adams County voted for the Democratic candidate.


United States presidential election in Iowa, 1976
Party Candidate Votes %
Republican Gerald Ford (inc.) 152,470 51.66%
Democratic Jimmy Carter 136,078 45.80%
American Thomas Anderson 3,698 1.24%
Independent Eugene McCarthy 2,952 0.99%
Write-In 896 0.30%
Total votes 297,094 100%


  1. ^ "1976 Presidential General Election Results - North Dakota". Retrieved January 7, 2017.
  2. ^