Talk:Rose (mathematics)

Latest comment: 3 years ago by 2601:140:8980:4B20:528:3DF3:2917:4EDF in topic Roses specified by other curves

Lissajous edit

This seems to be quite comparable to Lissajous curves. --Abdull 18:53, 27 May 2006 (UTC)Reply

If the point is that a lissajous curve can specify a rose, please find the parameters for the eqivalence. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:05, 20 February 2021 (UTC)Reply

Merge from/new Rhodonea article edit

I agree. I would have suggested/done the same myself if only I could have remembered the name of the Rose (mathematics) article. —David Eppstein 05:51, 22 February 2007 (UTC)Reply

Definitely agree. No reason to have two articles, especially as they are both so minimal. Doctormatt 16:45, 22 February 2007 (UTC)Reply
Agree with proposed merge. Gandalf61 17:33, 22 February 2007 (UTC)Reply

Pictures edit

I just noticed that while the article gives the rose in terms of cosine, the pictures are all for sine. Do we

  • change the article to make sine the basic one (and relate cosine to it as a rotation)?
  • change the pictures? (Sounds like a pain.)
  • change the captions on the pictures to be more specific?

VectorPosse 17:09, 4 April 2007 (UTC)Reply

Ack. I'll change the images (the second one is okay). It'll be done in a few hours, probably. Cheers, Doctormatt 20:04, 4 April 2007 (UTC)Reply
I updated the seven petal image and added info to the "rose gallery" image to make it clear these are r=sin k \theta. I think this works. Cheers, Doctormatt 04:36, 5 April 2007 (UTC)Reply

Area edit

The right side of the Area formula suggests that the Area is independent of k! —Preceding unsigned comment added by 91.36.95.125 (talk) 02:54, 30 December 2007 (UTC)Reply

The area of each petal is dependent on k. See the article. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 23:58, 19 February 2021 (UTC)Reply

For irrational k the curve won't fill the unit disc edit

In that case the curve will be dense in the unit disc, but it won't "fill" it completely. To see this, just imagine a circle around the origin or a straight line that crosses the unit disc. The rose will cross or touch this line/circle just countably inifinite times, but there are more than countably infinite points the rose would have to hit in order to fill the entire disc. --Georg-Johann (talk) 18:00, 4 September 2010 (UTC)Reply

"offset parameter" edit

Here are some images generated from the generalized rose-limaçon equation r=b+sin(aθ): ... AnonMoos (talk) 21:44, 23 July 2014 (UTC)Reply

3d Rose Curves edit

What are these things called? https://www.youtube.com/watch?v=Y7utC53CNs4

Do they have a name? Do they deserve a name? Am I over stepping any boundaries calling them 3d Rose Curves? -- 18:14, 28 March 2015‎ Tejolson

2018 edit

I am unable to reproduce the current Rose-rhodonea-curve-7x9-chart-improved.svg using r=cos(k \theta). Here is what I got instead:

 
Rose rhodonea curve

Is there anything I am missing, or the figure in question is not properly computed? — Preceding unsigned comment added by HamdiSahloul (talkcontribs) 16:32, 3 December 2018 (UTC)Reply

Something is very wrong. Check against curves generated using desmos on desmos.com. The chart asvof this date compares favorably. (Read the caption.) 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 00:09, 20 February 2021 (UTC)Reply


Limaçon article edit

Roses are sinusoids with no offset parameter. Those things are limacons. There is an article on them: limaçon. 2601:140:8980:4B20:DAA:DAE7:8979:2DE5 (talk) 01:56, 5 February 2021 (UTC)Reply

Missing video edit

The video is no longer available. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:02, 20 February 2021 (UTC)Reply

Roses specified by other curves edit

This article needs a section on other curve types that specify roses like the hypotrochoid. Such a section which enrich understanding of both types greatly! 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:49, 20 February 2021 (UTC)Reply