The 1991 Indian Challenge was an invitational non-ranking snooker tournament held in India in 1991. Stephen Hendry won the title, defeating John Parrott 9–5 in the final, and received £20,000 prize money. Parrott compiled the highest break of the tournament, 132, in the semi-final, having made a 127 break in the preceding frame.[1][2]

1991 Indian Challenge
Tournament information
VenueTaj Palace Intercontinental Hotel, Delhi
CountryIndia
FormatNon-ranking event
Winner's share£20,000
Highest break John Parrott (ENG) 132
Final
Champion Stephen Hendry (SCO)
Runner-up John Parrott (ENG)
Score9–5

Results edit

[1]

First round
Best-of-9 frames
Quarter-finals
Best-of-9 frames
Semi-finals
Best-of-9 frames
Final
Best-of-17 frames
        
  John Parrott (ENG) 5
  Michael Ferreira (IND) 0
  John Parrott 5
  Mike Hallett 2
  Mike Hallett (ENG) 5
  Dennis Taylor (NIR) 2
  John Parrott 5
  Gary Wilkinson 3
  Gary Wilkinson (ENG) 5
  Chuchart Trirattanapradit (THA) 2
  Gary Wilkinson 5
  Jimmy White 2
  Jimmy White (ENG) 5
  Atul Agarwal (IND) 0
  John Parrott 5
  Stephen Hendry 9
  Stephen Hendry (SCO) 5
  Sonic Multani (IND) 4
  Stephen Hendry 5
  Steve James 3
  Steve James (ENG) 5
  Terry Griffiths (WAL) 2
  Stephen Hendry 5
  Steve Davis 3
  Neal Foulds (ENG) 5
  James Wattana (THA) 3
  Neal Foulds 2
  Steve Davis 5
  Steve Davis (ENG) 5
  Geet Sethi (IND) 0

References edit

  1. ^ a b "Hendry survives scare and wins again". Snooker Scene. Birmingham: Everton's News Agency. October 1991. p. 23.
  2. ^ Turner, Chris. "Other Non-Ranking and Invition Events". cajt.pwp.blueyonder.co.uk. Chris Turner's Snooker Archive. Archived from the original on 16 February 2012. Retrieved 24 October 2012.