1956 French Championships (tennis)

(Redirected from 1956 French Amateur)

The 1956 French Championships (now known as the French Open) was a tennis tournament that took place on the outdoor clay courts at the Stade Roland-Garros in Paris, France. The tournament ran from 15 May until 26 May. It was the 60th staging of the French Championships, and the second Grand Slam tennis event of 1956. Lew Hoad and Althea Gibson won the singles titles.

1956 French Championships
Date15–26 May 1956
Edition55
Category26th Grand Slam (ITF)
SurfaceClay
LocationParis (XVIe), France
VenueStade Roland Garros
Champions
Men's singles
Australia Lew Hoad[1]
Women's singles
United States Althea Gibson[2]
Men's doubles
Australia Don Candy / United States Robert Perry
Women's doubles
United Kingdom Angela Buxton / United States Althea Gibson
Mixed doubles
Australia Thelma Coyne Long / Chile Luis Ayala
← 1955 · French Championships · 1957 →

Finals

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Men's singles

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  Lew Hoad defeated   Sven Davidson 6–4, 8–6, 6–3

Women's singles

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  Althea Gibson defeated   Angela Mortimer 6–0, 12–10

Men's doubles

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  Don Candy /   Robert Perry defeated   Ashley Cooper /   Lew Hoad 7–5, 6–3, 6–3

Women's doubles

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  Angela Buxton /   Althea Gibson defeated   Darlene Hard /   Dorothy Head Knode 6–8, 8–6, 6–1

Mixed doubles

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  Thelma Coyne Long /   Luis Ayala defeated   Darlene Hard /   Bob Howe 4–6, 6–4, 6–1

References

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  1. ^ "Roland-Garros 1956 (Grand Slam) - Men singles" (PDF). Fédération Française de Tennis (FFT). Archived from the original (PDF) on 2013-12-03. Retrieved 2013-11-29.
  2. ^ "Roland-Garros 1956 (Grand Slam) - Women singles" (PDF). Fédération Française de Tennis (FFT). Archived from the original (PDF) on 2016-03-03. Retrieved 2013-11-29.
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Preceded by Grand Slams Succeeded by