1956 French Championships – Men's doubles

The 1956 French Championships men's doubles was one of the competitions of the 1956 French Championships, a tennis tournament held at the Stade Roland-Garros in Paris, France from 15 May until 26 May 1956. The matches were played in a best-of-five sets format. Don Candy and Bob Perry defeated Ashley Cooper and Lew Hoad 7–5, 6–3, 6–3 in the final to win the title. The winning teams received 25,000 French franc per player with the runner-up players earning 12,000 Fr and the four losing semifinalists receiving 6,000 Fr each.[2][3][4]

Men's doubles
1956 French Championships
Final
ChampionAustralia Don Candy
United States Bob Perry[1]
Runner-upAustralia Ashley Cooper
Australia Lew Hoad[1]
Score7–5, 6–3, 6–3
Details
Draw32
Events
Singles men women
Doubles men women
← 1955 · French Championships · 1957 →

Draw

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Finals

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Quarterfinals Semifinals Final
                     
  Nicola Pietrangeli
  Orlando Sirola
3 7 4 4
  Don Candy
  Bob Perry
6 5 6 6
  Don Candy
  Bob Perry
6 3 11 9
  Luis Ayala
  Sven Davidson
3 6 9 7
  Luis Ayala
  Sven Davidson
4 6 6 6
  Gordon Forbes
  Ian Vermaak
6 4 4 4
  Don Candy
  Bob Perry
7 6 6
  Ashley Cooper
  Lew Hoad
5 3 3
  Andrés Gimeno
  Fernando Olazaga
5 2 5
  Jaroslav Drobný
  Trevor Fancutt
7 6 7
  Jaroslav Drobný
  Trevor Fancutt
4 2 8
  Ashley Cooper
  Lew Hoad
6 6 10
  Jacques Brichant
  Gino Mezzi
1 1 3
  Ashley Cooper
  Lew Hoad
6 6 6

References

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  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. pp. 108, 400. ISBN 978-0942257700.
  2. ^ "Championnats Internationaux de France". "Smash" (in French). 17 (75): 14. June–July 1956.
  3. ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 204–205, 210–211.
  4. ^ "Scratch Pair Win French Doubles". The Canberra Times. Vol. 30, no. 8, 859. Australian Capital Territory, Australia. 29 May 1956. p. 6 – via National Library of Australia.
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