1929 U.S. National Championships – Women's singles

First-seeded Helen Wills defeated Phoebe Holcroft Watson 6–4, 6–2 in the final to win the women's singles tennis title at the 1929 U.S. National Championships. It was her sixth U.S. National singles title and her third in a row.[1][2][3]

Women's singles
1929 U.S. National Championships
Final
ChampionUnited States Helen Wills
Runner-upUnited Kingdom Phoebe Holcroft Watson[1]
Score6–4, 6–2
Events
Singles men women
Doubles men women
← 1928 · U.S. National Championships · 1930 →

Seeds edit

The tournament used a list of eight U.S. players and six foreign players for seeding the women's singles event. Helen Wills is the champion; others show in brackets the round in which they were eliminated.[4]

Draw edit

Final eight edit

Quarterfinals Semifinals Finals
               
1   Helen Wills 6 6
(3)   Peggy Saunders Michell 0 1
1   Helen Wills 6 6
4   Molla Bjurstedt Mallory 0 0
4   Molla Bjurstedt Mallory 6 6
(1)   Betty Nuthall 3 3
1   Helen Wills 6 6
(2)   Phoebe Holcroft Watson 4 2
3   Edith Cross 6 1 3
(2)   Phoebe Holcroft Watson 2 6 6
(2)   Phoebe Holcroft Watson 6 3 6
2   Helen Jacobs 1 6 1
6   Mary Greef 2 2
2   Helen Jacobs 6 6

References edit

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 469. ISBN 978-0942257700.
  2. ^ "Helen Wills Wins National Tilt in Eighteen Minutes". The Lewiston Daily Sun. AP. August 20, 1929. p. Eleven – via Google News Archive.
  3. ^ "Helen Wills Takes Sixth National Title". Chicago Tribune. AP. August 25, 1929. p. 1, Part 2.
  4. ^ "Helen Wills Likely to Play her Rival". Sarasota Herald-Tribune. AP. August 14, 1929. p. Six – via Google News Archive.
Preceded by Grand Slam women's singles Succeeded by