The 1873 Rhode Island gubernatorial election was held on 2 April 1873 in order to elect the governor of Rhode Island. Republican nominee Henry Howard defeated Democratic nominee Benjamin G. Chace.[1]
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 County results Howard: 60–70% 70–80% >90% | |||||||||||||||||
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General election
editOn election day, 2 April 1873, Republican nominee Henry Howard won the election by a margin of 5,870 votes against his opponent Democratic nominee Benjamin G. Chace, thereby retaining Republican control over the office of governor. Howard was sworn in as the 32nd governor of Rhode Island on 6 May 1873.[2]
Results
edit| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Henry Howard | 9,656 | 71.68 | |
| Democratic | Benjamin G. Chace | 3,786 | 28.11 | |
| Scattering | 29 | 0.21 | ||
| Total votes | 13,471 | 100.00 | ||
| Republican hold | ||||
References
edit- ^ "Henry Howard". National Governors Association. Retrieved 8 April 2024.
- ^ "RI Governor". ourcampaigns.com. 6 October 2005. Retrieved 8 April 2024.