The 1868 Rhode Island gubernatorial election was held on 1 April 1868 in order to elect the Governor of Rhode Island. Incumbent Republican Governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the 1866 and 1867 election.[1]
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General election edit
On election day, 1 April 1868, incumbent Republican Governor Ambrose Burnside won re-election by a margin of 6,648 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of Governor. Burnside was sworn in for his third term on 4 May 1868.[2]
Results edit
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Ambrose Burnside (incumbent) | 10,038 | 74.69 | |
| Democratic | Lyman Pierce | 3,390 | 25.23 | |
| Scattering | 11 | 0.08 | ||
| Total votes | 13,439 | 100.00 | ||
| Republican hold | ||||
References edit
- ^ "Ambrose Burnside". National Governors Association. Retrieved 7 April 2024.
- ^ "RI Governor". ourcampaigns.com. 26 July 2005. Retrieved 7 April 2024.