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1928 United States presidential election in Wisconsin

The 1928 United States presidential election in Wisconsin was held on November 6, 1928. Wisconsin voters chose thirteen electors to the Electoral College, who voted for president and vice president.

United States presidential election, 1928

← 1924 November 6, 1928 1932 →
  Herbert Hoover - NARA - 532049.tif AlfredSmith.png
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 13 0
Popular vote 544,205 450,259
Percentage 53.52% 44.28%

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

Republican Party candidate Herbert Hoover won the state with 54% of the popular vote, winning Wisconsin's thirteen electoral votes.[1] As of the 2016 presidential election, this is the last election in which Douglas County voted for the Republican candidate.

ResultsEdit

United States presidential election in Wisconsin, 1928
Party Candidate Votes Percentage Electoral votes
Republican Herbert Hoover 544,205 53.52% 13
Democratic Al Smith 450,259 44.28% 0
Socialist Norman Thomas 18,213 1.79% 0
Totals 1,012,677 100.0% 13

ReferencesEdit

  1. ^ "1928 Presidential General Election Results - Wisconsin". Retrieved August 19, 2016.