Talk:Von Mises–Fisher distribution
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Presumably it generalizes to a Mises distribution (circle) for p=3, not p=2, since circles are 2-dimensional and the von Mises-Fisher distribution is p-1 dimensional. There might be something I missed though, so I'm not going to change it without confirmation. --Smári McCarthy 13:16, 19 July 2006 (UTC)
The circle is not 2-dimensional, but 1-dimensional, as any point on the circle can be uniquely identified by a singe angle. Similarly, the sphere is 2-dimensional, as each point can be identified by a pair of polar angles. However, you do need an extra dimension to 'represent' the circle or sphere without distortions. --TomixDf Mon Aug 7 12:02:13 2006
The R notation is undefined edit
what is it ? — Preceding unsigned comment added by 92.133.97.155 (talk • contribs)
- I think the "mean resultant vector". See Directional statistics. --Tobias1984 (talk) 14:13, 29 July 2015 (UTC)
Someone please clarify which von Mises edit
Was it Ludwig von Mises, the Austrian economist? The article doesn't say, nor does the article on the von Mises distribution. I was surprised recently to find out that LvM had in fact done early work on algorithmic randomness. --Trovatore (talk) 01:17, 23 February 2008 (UTC)
It was his brother, Richard von Mises. Tomixdf (talk) 09:04, 23 February 2008 (UTC)
Mardia reference missing edit
What is the Mardia (2000) reference? — Preceding unsigned comment added by 128.243.253.117 (talk) 13:03, 13 June 2011 (UTC)
Polar coordinates? edit
The article first states that x is a p-dimensional unit vector. Then there is a comment that says "Note that the equations above apply for polar coordinates only.". I don't believe this is the case? The references seem to refer to x in R^(p). If I've missed something, then surely at the least these are hyperspherical coordinates, not polar?
I tried testing this in a very simple 2D (circle) case, and using cartesian coordinates gave me the expected result --TheKrimsonChin (talk) 15:35, 27 February 2015 (UTC)
Indeed the reported functions are for cartesian, not polar(spherical in reality) coordinates, I'm going to fix it. [Silvano Galliani] — Preceding unsigned comment added by 192.33.89.33 (talk) 08:11, 26 June 2015 (UTC)