Talk:Stellated truncated hexahedron

Latest comment: 4 years ago by Double sharp in topic Convex core is nonuniform?

Convex core is nonuniform? edit

What's the definition of "convex core" being used here? The convex core (Stella definition) only has the triangles, making a regular octahedron. So I am interested to know what is meant. Double sharp (talk) 10:44, 1 May 2013 (UTC)Reply

Convex core means "stellation core".???‽‽‽!!!?‽!?‽!?‽!? 06:22, 5 May 2013 (UTC)Reply
The core is the central volume of all the face-planes, and is convex by definition. So that core apparently isn't a uniform polyhedron, so it's a stellation of a nonuniform convex polyhedron. Tom Ruen (talk) 19:06, 5 May 2013 (UTC)Reply
Its core (surely convex) is a regular octahedron. This does not imply that this polyhedron is a stellation of the regular octahedron. --Little bishop (talk) 00:44, 16 September 2019 (UTC)Reply

Well, in 2013 someone claimed the core is a regular octahedron, and me now. It looks just obvious, we don't need a mathematical proof for that. I think it's time to fix this insane mistake of the 'nonuniform convex core'... Specifically I propose to change this: "its convex 'core' is not a uniform polyhedron", with this: "its core is a regular octahedron". Either that or we just avoid speaking about its core (as it is for all the other uniform star polyhedra): better to tell nothing rather than tell something wrong. --Little bishop (talk) 12:58, 21 September 2019 (UTC)Reply

The eight triangles correspond with the triangles in a truncated cube, and therefore also create the octahedral core you mention. That doesn't mean this isn't a stellation of the truncated cube: it most certainly is. If it were a stellation of the octahedron, where would the octagrammic faces come from? I propose changing the controversial sentence to the following.

Even though the stellated truncated hexahedron is a stellation of the truncated hexahedron, its core is a regular octahedron.

OfficialURL (talk) 20:07, 18 April 2020 (UTC)Reply

@OfficialURL: Sure, that's fine with me.
P.S. This is why I prefer the names quasitruncated cube or stellatruncated cube for this polyhedron. Double sharp (talk) 03:44, 19 April 2020 (UTC)Reply