Stokes formula

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The article said

The terminal velocites of any particle in any media can be calculated using Stoke's Law given by u0A =d2Ag (ρA − ρ) /18ü

But this is worthless without an idea what the paramters stand for and what units to use. (It may also be miswritten). We can put it back after we figure out what, precisely, it is trying to say (or just say that it depends on the size, mass, etc.) RJFJR (talk) 17:54, 24 January 2009 (UTC)Reply

It's not strictly true either, since stoke's law applies to particles say in the range of 1 - 20 microns diameter in air. For smaller particles, noncontinuum effects (Cunningham correction factor) are important, and for larger particles the assumptions in stokes law (neglecting inertial forces) are wrong. 99.240.72.110 (talk) 19:49, 18 December 2010 (UTC)Reply

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Participate in the deletion discussion at the nomination page. —Community Tech bot (talk) 15:59, 27 January 2021 (UTC)Reply