Semenov-Tian-Shansky Peak (Russian: Пик Семёнова-Тяньшанского, romanized: Pik Semonova-Tyan'shanskogo, Kyrgyz: Аламүдүн чокусу, romanized: Alamüdün çokusu, lit. 'Alamedin Peak') is a mountain in the Kyrgyz Ala-Too Range of the Tian Shan. It is located in Ala Archa National Park in Kyrgyzstan. It is the tallest mountain in the Kyrgyz Ala-Too Range and is an Ultra with a prominence of 2231m.[1]
| Semenov-Tian-Shansky Peak | |
|---|---|
| Pik Semonova-Tyan'shanskogo, Alamedin Peak | |
 The view from Uchitel Peak in the northwest | |
| Highest point | |
| Elevation | 4,895 m (16,060 ft) |
| Prominence | 2,231 m (7,320 ft) |
| Isolation | 233.57 km (145.13 mi)  |
| Coordinates | 42°31′16″N 74°34′18″E / 42.52111°N 74.57167°E |
| Geography | |
  Semenov-Tian-Shansky Peak | |
| Parent range | Kyrgyz Ala-Too Range, Tian Shan |
The mountain is situated between the Ala-Archa River to the west and the Alamedin River to the east.
History edit
The peak is named for the Russian geographer Peter Semenov-Tian-Shansky.