2019 San Benedetto Tennis Cup – Doubles

Julian Ocleppo and Andrea Vavassori were the defending champions but only Vavassori chose to defend his title, partnering Andrea Pellegrino.[1] Vavassori lost in the semifinals to Ivan and Matej Sabanov.

Doubles
2019 San Benedetto Tennis Cup
Final
ChampionsCroatia Ivan Sabanov
Croatia Matej Sabanov
Runners-upPeru Sergio Galdós
Peru Juan Pablo Varillas
Score6–4, 4–6, [10–5]
Events
Singles Doubles
← 2018 · San Benedetto Tennis Cup · 2022 →

Sabanov and Sabanov won the title after defeating Sergio Galdós and Juan Pablo Varillas 6–4, 4–6, [10–5] in the final.

Seeds edit

Draw edit

Key edit

First round Quarterfinals Semifinals Final
1   A Pellegrino
  A Vavassori
6 6
  DE Galán
  S Giraldo
w/o   DE Galán
  S Giraldo
4 2
  MF Descotte
  T-l Wu
1   A Pellegrino
  A Vavassori
6 4 [10]
3   E Gómez
  LD Martínez
  I Sabanov
  M Sabanov
3 6 [12]
  I Sabanov
  M Sabanov
w/o   I Sabanov
  M Sabanov
6 6
WC   Riccardo Balzerani
  F Forti
3 6 [8]   R Cid Subervi
  J Hernández-Fernández
1 2
  R Cid Subervi
  J Hernández-Fernández
6 4 [10]   I Sabanov
  M Sabanov
6 4 [10]
  V Šafránek
  J Šátral
6 3 [9] 4   S Galdós
  JP Varillas
4 6 [5]
ITF   Alexander Igoshin
  R Safiullin
1 6 [4]r   V Šafránek
  J Šátral
0 4
ITF   R Bonadio
  Jeroen Vanneste
6 3 [7] 4   S Galdós
  JP Varillas
6 6
4   S Galdós
  JP Varillas
1 6 [10] 4   S Galdós
  JP Varillas
4 6 [10]
  A Bega
  V Durasovic
7 7 2   A Siljeström
  S Walków
6 1 [6]
  M Guinard
  A Müller
5 5   A Bega
  V Durasovic
5 3
WC   A Basso
  W Trusendi
4 4 2   A Siljeström
  S Walków
7 6
2   A Siljeström
  S Walków
6 6

References edit

  1. ^ "Player profile". Archived from the original on 2018-07-04. Retrieved 2019-07-11.

External links edit