2019 Murray Trophy – Glasgow – Doubles

Gerard Granollers and Guillermo Olaso were the defending champions[1] but chose not to defend their title.

Glasgow – Doubles
2019 Murray Trophy – Glasgow
Final
ChampionsBelgium Ruben Bemelmans
Germany Daniel Masur
Runners-upUnited Kingdom Jamie Murray
Australia John-Patrick Smith
Score4–6, 6–3, [10–8]
Events
Singles Doubles
← 2018 · Murray Trophy – Glasgow · 2020 →

Ruben Bemelmans and Daniel Masur won the title after defeating Jamie Murray and John-Patrick Smith 4–6, 6–3, [10–8] in the final.

Seeds

edit

Draw

edit
First round Quarterfinals Semifinals Final
1   J Murray
  J-P Smith
6 6
WC   Marshall Tutu
  David Wright
4 2 1   J Murray
  J-P Smith
6 6
Alt   A Çelikbilek
  C İlkel
77 78 Alt   A Çelikbilek
  C İlkel
3 4
  H Heliövaara
  E Ruusuvuori
65 66 1   J Murray
  J-P Smith
6 6
4   K Drzewiecki
  S Walków
3 6 [10]   M Gengel
  R Ramanathan
2 3
WC   L Johnson
  Mark Whitehouse
6 3 [3] 4   K Drzewiecki
  S Walków
4 6 [3]
  M Gengel
  R Ramanathan
7 79   M Gengel
  R Ramanathan
6 3 [10]
  S Clayton
  L Glasspool
5 67 1   J Murray
  J-P Smith
6 3 [8]
  N Kuhn
  J Rodionov
w/o   R Bemelmans
  D Masur
4 6 [10]
  G Blancaneaux
  A Rinderknech
  N Kuhn
  J Rodionov
  R Bemelmans
  D Masur
77 6   R Bemelmans
  D Masur
w/o
3   A Göransson
  S Verbeek
62 4   R Bemelmans
  D Masur
6 4 [11]
  J Ocleppo
  R Ortega Olmedo
64 5 2   N Lammons
  A Šančić
4 6 [9]
  Q Halys
  M Martineau
77 7   Q Halys
  M Martineau
4 2
  R Gonzales
  A Siljeström
4 63 2   N Lammons
  A Šančić
6 6
2   N Lammons
  A Šančić
6 77

References

edit
  1. ^ "Britain's Jonny O'Mara & Scott Clayton lose Glasgow Trophy doubles final to Spanish duo". May 6, 2018 – via www.bbc.com.