2004 ATP Buenos Aires – Doubles

Mariano Hood and Sebastián Prieto were the defending champions but they competed with different partners that year, Hood with Lucas Arnold and Prieto with Martín García.

Doubles
2004 ATP Buenos Aires
Final
ChampionsArgentina Lucas Arnold
Argentina Mariano Hood
Runners-upArgentina Federico Browne
Argentina Diego Veronelli
Score7–5, 6–7(2–7), 6–4
Events
Singles Doubles
← 2003 · ATP Buenos Aires · 2005 →

García and Prieto lost in the first round to Juan Ignacio Chela and Nicolás Massú.

Arnold and Hood won in the final 7–5, 6–7(2–7), 6–4 against Federico Browne and Diego Veronelli.

Seeds edit

Draw edit

Key edit

First round Quarterfinals Semifinals Final
1   L Arnold
  M Hood
3 6 7
    M Fyrstenberg
  M Matkowski
6 3 5 1   L Arnold
  M Hood
77 6  
    A Calleri
  G Cañas
6 6       A Calleri
  G Cañas
60 2  
    D Ferrer
  R Ramírez Hidalgo
1 2   1   L Arnold
  M Hood
w/o    
4   M García
  S Prieto
3 4       J I Chela
  N Massú
     
    J I Chela
  N Massú
6 6       J I Chela
  N Massú
7 6  
WC   G Coria
  J Mónaco
6 6   WC   G Coria
  J Mónaco
5 2  
    Á López Morón
  A Portas
4 4   1   L Arnold
  M Hood
7 62 6
    D Bowen
  A Fisher
6     WC   F Browne
  D Veronelli
5 77 4
    J Acasuso
  D Sánchez
4 r       D Bowen
  A Fisher
2 4  
WC   F Browne
  D Veronelli
6 77   WC   F Browne
  D Veronelli
6 6  
3   S Aspelin
  M Bertolini
2 62   WC   F Browne
  D Veronelli
2 7 6
    E Artoni
  A Schneiter
6     2   F Čermák
  L Friedl
6 5 4
    M Vassallo Argüello
  F Volandri
2 r       E Artoni
  A Schneiter
66 4  
    N Lapentti
  M Rodríguez
4 2   2   F Čermák
  L Friedl
78 6  
2   F Čermák
  L Friedl
6 6  

References edit