1989 Virginia Slims of Indianapolis – Doubles

Larisa Savchenko and Natasha Zvereva were the defending champions, but Zvereva chose to compete at Worcester during the same week.

Doubles
1989 Virginia Slims of Indianapolis
Final
ChampionsUnited States Katrina Adams
United States Lori McNeil
Runners-upGermany Claudia Porwik
Soviet Union Larisa Savchenko
Score6–4, 6–4
Details
Draw16
Seeds4
Events
Singles Doubles
← 1988 · Virginia Slims of Indianapolis · 1990 →

Savchenko teamed up with Claudia Porwik and lost in the final to Katrina Adams and Lori McNeil. The score was 6–4, 6–4.[1]

Seeds edit

Draw edit

Key edit

Draw edit

First round Quarterfinals Semifinals Final
1   K Adams
  L McNeil
6 6
  R Baranski
  P Vásquez
3 3 1   K Adams
  L McNeil
6 6
  J Mundel
  G Purdy
6 4 0   S Foltz
  P Thorén
3 2
  S Foltz
  P Thorén
4 6 6 1   K Adams
  L McNeil
6 6 6
3   M Bollegraf
  K Maleeva
6 6 3   M Bollegraf
  K Maleeva
7 2 3
  S Amiach
  H Witvoet
4 3 3   M Bollegraf
  K Maleeva
4 6 6
  L Antonoplis
  G Miró
2 5   K Foxworth
  T Whittington
6 1 1
  K Foxworth
  T Whittington
6 7 1   K Adams
  L McNeil
6 6
  H Na
  R Reis
6 7 7 2   C Porwik
  L Savchenko
4 4
  H Cioffi
  A Frazier
7 5 6   H Na
  R Reis
4 6 5
  A Grousbeck
  M Norwood
2 3 4   N Medvedeva
  L Meskhi
6 3 7
4   N Medvedeva
  L Meskhi
6 6 4   N Medvedeva
  L Meskhi
6 6 4
  C Lindqvist
  J Pospíšilová
4 3 2   C Porwik
  L Savchenko
7 2 6
  M Lindström
  H Ludloff
6 6   M Lindström
  H Ludloff
3 4
  D Faber
  J Thomas
1 6 6 2   C Porwik
  L Savchenko
6 6
2   C Porwik
  L Savchenko
6 3 7

References edit

  1. ^ "WTA Indianapolis - Women's Doubles". Grand Slam History. Retrieved June 4, 2023. 1989; ADAMS Katrina, MCNEIL Lori; PORWIK Claudia, SAVCHENKO Larisa; 6-4, 6-4

External links edit