1988 WTA German Open – Doubles

Claudia Kohde-Kilsch and Helena Suková were the defending champions but lost in the final 6–2, 4–6, 6–4 against Isabelle Demongeot and Nathalie Tauziat.

Doubles
1988 WTA German Open
1987 Champions
Final
Champions
Runners-up
Score6–2, 4–6, 6–4
Events
Singles Doubles
← 1987 · WTA German Open · 1989 →

Seeds edit

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.

Draw edit

Key edit

Final edit

Final
     
1 2 6 4
5 6 4 6

Top half edit

First round Second round Quarterfinals Semifinals
1 6 6  
  6 6     1 3  
  3 2   1 6 6  
  6 6   6 3 2  
  4 4     5 1  
  2 3   6 7 6  
6 6 6   1 6 6  
8 2 1  
4 6 6  
  6 6     2 2  
  2 4   4 1 7 4
  6 6   8 6 5 6
  2 1     4 6  
  5 5   8 6 7  
8 7 7  

Bottom half edit

First round Second round Quarterfinals Semifinals
7 6 6  
  2 4   7 6 4 6
  2 3     3 6 2
  6 6   7 6 2 6
    S Cecchini
  S Goleš
0 6 6 3 3 6 3
  6 1 2     S Cecchini
  S Goleš
6 4  
3 7 6  
7 4 3  
5 6 4 6 5 6 6  
  0 6 3 5 6 6  
  6 6 6   0 3  
  7 2 4 5 4 6 7
  6 6     6 1 6
  1 4     2 6 7
2 6 2 6

References edit