1948 U.S. National Championships – Women's singles

Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the women's singles tennis title at the 1948 U.S. National Championships.[1][2]

Women's singles
1948 U.S. National Championships
Final
ChampionUnited States Margaret Osborne duPont[1]
Runner-upUnited States Louise Brough
Score4–6, 6–4, 15–13
Events
Singles men women
Doubles men women
← 1947 · U.S. National Championships · 1949 →

Seeds edit

The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]

  1.   Louise Brough (finalist)
  2.   Doris Hart (quarterfinals)
  3.   Margaret Osborne duPont (champion)
  4.   Pat Canning Todd (semifinals)
  5.   Shirley Fry (third round)
  6.   Beverly Baker (quarterfinals)
  7.   Gussy Moran (semifinals)

Draw edit

Key edit

Final eight edit

Quarterfinals Semifinals Finals
               
7   Gussy Moran 6 6
2   Doris Hart 4 4
7   Gussy Moran 8 4
3   Margaret Osborne duPont 10 6
3   Margaret Osborne duPont 1 6 6
  Beverly Baker 6 2 0
3   Margaret Osborne duPont 4 6 15
1   Louise Brough 6 4 13
1   Louise Brough 6 6
  Virginia Kovacs 3 2
1   Louise Brough 6 6
4   Pat Canning Todd 3 3
4   Pat Canning Todd 6 6
  Madge Vosters 3 1

References edit

  1. ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. ^ "Exciting Game for Tennis Title". The Cairns Post. Qld. September 21, 1948. p. 1 – via National Library of Australia.
  3. ^ G.P. Hughes, ed. (1949). Dunlop Lawn Tennis Annual and Almanack 1949. London: Ed. J. Burrow & Co. Ltd. pp. 159–164.
Preceded by Grand Slam women's singles Succeeded by