1928 United States presidential election in South Carolina

The 1928 United States presidential election in South Carolina took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.

1928 United States presidential election in South Carolina

← 1924 November 6, 1928 1932 →
  Unsuccessful 1928.jpg Herbert Hoover - NARA - 532049.jpg
Nominee Al Smith Herbert Hoover
Party Democratic Republican
Home state New York California
Running mate Joseph Taylor Robinson Charles Curtis
Electoral vote 9 0
Popular vote 62,700 5,858
Percentage 91.39% 8.54%

South Carolina Presidential Election Results 1928.svg
County Results
Smith
  70-80%
  80-90%
  90-100%


President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

South Carolina voted for the Democratic nominee, Governor Alfred E. Smith of New York, over the Republican nominee, Secretary of Commerce Herbert Hoover of California. Smith ran with Senator Joseph Taylor Robinson of Arkansas, while Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas.

Smith won South Carolina by a margin of 82.85%.

ResultsEdit

1928 United States presidential election in South Carolina[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Al Smith of New York Joseph Taylor Robinson of Arkansas 62,700 91.39% 9 100.00%
Republican Herbert Hoover of California Charles Curtis of Kansas 5,858 8.54% 0 0.00%
Socialist Norman Thomas of New York James Hudson Maurer of Pennsylvania 47 0.07% 0 0.00%
Total 68,605 100.00% 9 100.00%

ReferencesEdit

  1. ^ "1928 Presidential General Election Results - South Carolina". U.S. Election Atlas. Retrieved 23 December 2013.