1869 Vermont gubernatorial election

The 1869 Vermont gubernatorial election took place on September 7, 1869. Incumbent Republican John B. Page, per the "Mountain Rule",[1] did not run for re-election to another term as Governor of Vermont. Republican candidate Peter T. Washburn, who had served in the Vermont House of Representatives and as Adjutant General of the Vermont Militia, defeated Democratic candidate Homer W. Heaton, a former member of the Vermont House, to succeed him. The 1869 election was the final time the Governor of Vermont was elected for a one-year term; terms were changed to two years beginning in 1870.

1869 Vermont gubernatorial election

← 1868 September 7, 1869 (1869-09-07) 1870 →
  Peter T Washburn.jpg Homer W. Heaton Vermont politician.jpg
Candidate Peter T. Washburn Homer W. Heaton
Party Republican Democratic
Popular vote 31,834 11,455
Percentage 73.5% 26.4%

Governor before election

John B. Page

Elected Governor

Peter T. Washburn


1869 Vermont gubernatorial election[2]
Party Candidate Votes % ±%
Republican Peter T. Washburn 31,834 73.5 0.0
Democratic Homer W. Heaton 11,455 26.4 0.0
N/A Other 26 0.1 0.0
Total votes '43,315' '100'


  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 4 October 2015.
  2. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on 30 November 2014. Retrieved 4 October 2015.