1844 United States presidential election in New Hampshire

The 1844 United States presidential election in New Hampshire took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

1844 United States presidential election in New Hampshire

← 1840 November 1 - December 4, 1844 1848 →
  Polk 1849.jpg Clay 1848.jpg James Birney(Cropped).jpg
Nominee James K. Polk Henry Clay James G. Birney
Party Democratic Whig Liberty
Home state Tennessee Kentucky Michigan
Running mate George M. Dallas Theodore Frelinghuysen Thomas Morris
Electoral vote 6 0 0
Popular vote 27,160 17,866 4,161
Percentage 55.22% 36.32% 8.46%

President before election

John Tyler

Elected President

James K. Polk

New Hampshire voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay and Liberty candidate James G. Birney. Polk won New Hampshire by a margin of 18.9%.

With 8.46% of the popular vote, New Hampshire would prove to be James G. Birney's strongest state.[1]


1844 United States presidential election in New Hampshire[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James K. Polk of Tennessee George M. Dallas of Pennsylvania 27,160 55.22% 6 100.00%
Whig Henry Clay of Kentucky Theodore Frelinghuysen of New York 17,866 36.32% 0 0.00%
Liberty James G. Birney of Michigan Thomas Morris of Ohio 4,161 8.46% 0 0.00%
Total 49,187 100.00% 6 100.00%

See alsoEdit


  1. ^ "1844 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1844 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.