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1840 United States presidential election in New Hampshire

The 1840 United States presidential election in New Hampshire took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

1840 United States presidential election in New Hampshire

← 1836 October 30 – December 2, 1840 1844 →
  Van Buren.jpg Harrison crop.jpg
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate none John Tyler
Electoral vote 7 0
Popular vote 32,774 26,310
Percentage 54.66% 43.88%

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.

ResultsEdit

1840 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 32,774 54.66% 7 100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 26,310 43.88% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 872 1.45% 0 0.00%
Total 59,956 100.00% 7 100.00%

ReferencesEdit

  1. ^ "1840 Presidential General Election Results – New Hampshire". U.S. Election Atlas. Retrieved 23 December 2013.