1826 Delaware gubernatorial election

The 1826 Delaware gubernatorial election was held on October 3, 1826. Incumbent Federalist Governor Samuel Paynter was barred from seeking re-election to a second consecutive term. State Senator Charles Polk Jr. ran as the Federalist nominee to succeed Paynter, while 1823 Democratic-Republican nominee David Hazzard once again ran as his party's nominee. Polk ended up defeating Hazzard by a narrow margin, barely holding onto the governorship for the Federalists.[1]

1826 Delaware gubernatorial election

← 1823 (special) October 3, 1826 1829 →
  CharlesPolk.png DavidHazzard.png
Nominee Charles Polk Jr. David Hazzard
Party Federalist Democratic-Republican
Popular vote 4,333 4,051
Percentage 50.55% 48.23%

Governor before election

Samuel Paynter
Federalist

Elected Governor

Charles Polk Jr.
Federalist

General electionEdit

ResultsEdit

1826 Delaware gubernatorial election[2]
Party Candidate Votes % ±%
Federalist Charles Polk Jr. 4,333 50.55% -1.21%
Democratic-Republican David Hazzard 4,238 49.45% +1.21%
Majority 95 1.11% -2.43%
Turnout 8,571 100.00%
Federalist hold

ReferencesEdit

  1. ^ Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 180.
  2. ^ Dubin 2003, p. 27.

BibliographyEdit

  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.