Wikipedia:Reference desk/Archives/Mathematics/2018 February 20
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February 20
editAsking for an operator (moved from the science desk)
editIs there any operator whose commutator with the square root of Hamiltonian is a constant times that operator? i.e. or depending on Hamiltonian is either positive or negative.Sayan Ghosh 04:13, 20 February 2018 (UTC) — Preceding unsigned comment added by Sayan19ghosh99 (talk • contribs)
![{\displaystyle [{\sqrt {H}},\alpha ]=constant*\alpha }](https://wikimedia.org/api/rest_v1/media/math/render/svg/24bb4edee41f37924ee8c41e23533735ef039488)
![{\displaystyle [{\sqrt {-H}},\alpha ]=constant*\alpha }](https://wikimedia.org/api/rest_v1/media/math/render/svg/7f4e4fa9aec003fef5c190e291260a78a90b2b8b)
- This question should have been asked on the Math Desk. Edison (talk) 15:15, 20 February 2018 (UTC)
- Is this restricted to linear operators? You always have the trivial multiply by zero, giving the 0 result. Graeme Bartlett (talk) 07:08, 21 February 2018 (UTC)