Mass of universe (Mu ) Dimensional Radius (dr) Mass, yes good old relative mass (m) Linear Constant, 0.41520467836 (1)
e=-1(1/c^2), mc^2=1: thass right, your not drunk
e=[[(m/dr)+(m/1dr)]+[(m/2-m/dr)+(m/2-m/1dr)]c^2 m=[[(m/dr)+(m/1dr)]+[(m/2-m/dr)+(m/2-m/1dr)] e=[[(m/43.5964912277)+(m/0.41520467836)]+[(m/2-m/e)+(m/2-m/0.41520467836)] m=[[(m/e)+(m/0.41520467836)]+[(m/2-m/43.5964912277)+(m/2-m/0.41520467836)]
m=10, e=8.98755179e17 e/c^2=[[(10/43.5964912277)+(10/0.41520467836)]+[(10/2-10/8.98755179e17)+(10/2-10/0.41520467836)] e/c^2=10.2293762575 m=[[(10/8.98755179e17)+(10/0.41520467836)]+[(10/2-10/43.5964912277)+(10/2-10/0.41520467836)] m=9.77062374245
m=255, e=2.29182571e19 e/c^2=[[(255/43.5964912277)+(255/0.41520467836)]+[(255/2-255/2.29182571e19)+(255/2-255/0.41520467836)] m=[[(255/2.29182571e19)+(255/0.41520467836)]+[(255/2-255/43.5964912277)+(255/2-255/0.41520467836)] m=3.21555866e-9, e=289000000 e/c^2=[[(3.21555866e-9/43.5964912277)+(3.21555866e-9/0.41520467836)]+[(3.21555866e-9/2-3.21555866e-9/289000000)+(3.21555866e-9/2-3.21555866e-9/0.41520467836)] m=[[(3.21555866e-9/289000000)+(3.21555866e-9/0.41520467836)]+[(3.21555866e-9/2-3.21555866e-9/43.5964912277)+(3.21555866e-9/2-3.21555866e-9/0.41520467836)]
m=6.5115*10^-9, e=585224435
Redacted Redacted
m=9e-31, e=8.08879661e-14 e/c^2=[[(9e-31/43.5964912277)+(9e-31/0.41520467836)]+[(9e-31/2-9e-31/8.08879661e-14)+(9e-31/2-9e-31/0.41520467836)] e/c^2=-1.1126501e-17 m=[[(9e-31/8.08879661e-14)+(9e-31/0.41520467836)]+[(9e-31/2-9e-31/43.5964912277)+(9e-31/2-9e-31/0.41520467836)] m=1.1126501e-17
This stupid f-ing chart says: as the mass of an object drops below the speed of light as it accelerates, there is a point that its energy and mass become related: e=-1(1/c^2), mc^2=1. How can energy be relative to mass, if energy divided by the speed of light squared is equal to the exact opposite of what mass times the speed of light squared is equal too?
Because the following equation ONLY works for the mass of the universe,
Mu-[(Mu/1dr)+(Mu/2dr)+(Mu/3dr)+(Mu/4dr)+(Mu/5dr)+(Mu/6dr)=s1 Mu-[(Mu/2-Mu/1dr)+(Mu/2-Mu/2dr)+(Mu/2-Mu/3dr)+(Mu/2-Mu/4dr)+(Mu/2-Mu/5dr)+(Mu/2-Mu6dr)=s2 s1+s2=-1(Mu)
3*10^55-[(7.2253521e+55)+(2.4084507e+55)+(1.2042254e+55)+(7.2253521e+54)+(2.1251036e+54)+(1.3894908e+54]=-8.9120229e+55, s2 3*10^55-[(-5.7253521e+55)+(-9.084507e+54)+(2.9577465e+54)+(7.7746479e+54)+(1.2874896e+55)+(1.3610509e+55)]=5.9120229e+55, s2 s1+s2, (-8.9120229e+55)+5.9120229e+55=-3*10^55
and this equation works both for the mass of the universe and masses less than that,
v1=3e55-[(3e55/43.5964912277)+(3e55/0.41520467836)]
v2=3e55-[(3e55/2)-(3e55/43.596491227)+[(3e55/2)-(3e55/0.41520467836)]]
3e55=[3e55-[(3e55/43.5964912277)+(3e55/0.41520467836)]]+[3e55-[(3e55/2)-(3e55/43.596491227)+[(3e55/2)-(3e55/0.41520467836)]]]
v1+v2=3e55
m=[m-[(m/dr)+(m/1dr)]]+[m-[(m/2)-(m/dr)+[(m/2)-(m/1dr)]]
Mass it's self must be equal to:
m=[[(m/dr)+(m/1dr)]+[(m/2-m/dr)+(m/2-m/1dr)]
Variable proofs:
(123/19/2)-[(124/18/2)]=-0.20760233918, f2
-1dr=(f2*2)*[(3-1)/2]=-0.41520467836
-2dr=(f2*2)*[(7-1)/2]=-1.24561403508
1dr=(0.20760233918*2)*[(3-1)/2]=0.41520467836
2dr=(0.20760233918*2)*[(7-1)/2]=1.24561403508
3dr=(0.20760233918*2)*[(13-1)/2]=2.49122807016
4dr=(0.20760233918*2)*[(21-1)/2]=4.1520467836
5dr=(0.20760233918*2)*[(69-1)/2]=14.1169590642
6dr=(0.20760233918*2)*[(105-1)/2]=21.5906432747
Mu=3*10^55
Mu/1dr=7.2253521e+55
(Mu/2-Mu/1dr): 3*10^55/2-(3*10^55/0.41520467836)=-5.7253521e+55
Mu/2dr=2.4084507e+55
(Mu/2-Mu/2dr): 3*10^55/2-(3*10^55/1.24561403508)=-9.084507e+54
Mu/3dr=1.2042254e+55
(Mu/2-Mu/3dr): 3*10^55/2-(3*10^55/2.49122807016)=2.9577465e+54
Mu/4dr=7.2253521e+54
Mu/2-Mu/4dr=7.7746479e+54
Mu/5dr=2.1251036e+54
(Mu/2-Mu/5dr): 3*10^55/2-(3*10^55/14.1169590642)=1.2874896e+55
Mu/6dr=1.3894908e+54
(Mu/2-Mu/6dr): 3*10^55/2-(3*10^55/21.5906432747)=1.3610509e+55
if,
Our theoretical 'surface processes'
Mu-[(1.2042254e+55)+(7.2253521e+54)+(2.1251036e+54)+(1.3894908e+54)]=7.2177995e+54
3*10^55/7.2177995e+54=4dr,
Our theoretical 'sub-surface processes'
Mu-[(2.9577465e+54)+(7.7746479e+54)+(1.2874896e+55)+(1.3610509e+55)]=-7.2177994e+54
1.4435599e+55 switches flipped
Lets try and peek from a lower dimension, to a higher one, 3 looking into 4
(7.7746479e+54)-(1.2042254e+55), or (Mu/2-4dr)-(Mu/3dr)=<0, time stops
While processing this:
3*10^55-[(1.3610509e+55)+(1.3894908e+54)]=1.5e+55
1.5e+55-[(7.2253521e+54)+(2.1251036e+54)], the fourth dimension is visible but,
1.5e+55-[(1.2042254e+55)+(7.2253521e+54)+(2.1251036e+54)], viewing the third is impossible, and net negative
But,
This can be processed:
3*10^55-[(1.3610509e+55)+(1.3894908e+54)+(1.2874896e+55)+(2.1251036e+54)]
Now, lets find the missing dimension of antimatter (we add in our one and two dimensions)
3*10^55-[(7.2253521e+55)+(2.4084507e+55)+(1.2042254e+55)+(7.2253521e+54)+(2.1251036e+54)+(1.3894908e+54]=-8.9120229e+55
3*10^55-[(-5.7253521e+55)+(-9.084507e+54)+(2.9577465e+54)+(7.7746479e+54)+(1.2874896e+55)+(1.3610509e+55)]=5.9120229e+55
(-8.9120229e+55)+5.9120229e+55=-3*10^55
then,
A 1d point,
wg=[(7.2253521e+55*-5.7253521e+55)/0.41520467836]*6.67408e-11
ng=(7.2253521e+55*-5.7253521e+55)/2.49122807016
Process:
3e55-[(7.2253521e+55)+(-5.7253521e+55)]=1.5e+55
A 3d process
3e55-[(1.2042254e+55)+(2.9577465e+54)]=1.5e+55
So processing a single point in three dimensions, is equal to:
1.5e+55-1.5e+55=0
The observation principle.
But, if we process our electron two dimensionally via a cpu:
wg=[(2.4084507e+55*-9.084507e+54)/0.41520467836]*6.67408e-11
ng=(2.4084507e+55*-9.084507e+54)/2.49122807016
(wg/ng)/(4dr*2)=c
Now, we check if we have enough to process:
3e55-[(2.4084507e+55)+(-9.084507e+54)]=1.5e+55
[(7.7746479e+54)*2]-1.5e+55=5.492958e+53
and there is enough to process four dimensionally (I think :-!)
{
If
[((3e55*10^500)/2-(3e55*10^500)/1.24561403508)/0.41520467836]*6.67408e-11=wg
[((3e55*10^500)/2-(3e55*10^500)/1.24561403508)/2.49122807016=ng
(wg/ng)/4dr*2=c
}
Proving insanity is relative.. Alternativity
We gots links,
https://en.wikipedia.org/wiki/List_of_nearest_black_holes
https://en.wikipedia.org/wiki/Alpha_Centauri
https://en.wikipedia.org/wiki/Wolf_359
https://en.wikipedia.org/wiki/Cygnus_X-1
https://en.wikipedia.org/wiki/MACS0647-JD
https://www.google.ca/search?client=opera&q=hubble+constant+value&sourceid=opera&ie=UTF-8&oe=UTF-8
brad bIll bUsch
UBandI iMages
Why you may ask? Because there is no one left to submit a unified field theory to }
bRad bIll bUsch UBandI iMages
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