arccos ( a ^ ⋅ b ^ ) {\displaystyle \arccos \left({\hat {a}}\cdot {\hat {b}}\right)} where arccos = cos − 1 {\displaystyle \arccos =\cos ^{-1}} NightKhaos (talk) 21:34, 30 March 2009 (UTC)
a 1 2 + a 2 2 b 1 2 + b 2 2 sin [ arccos ( a 1 b 1 + a 2 b 2 ) ] {\displaystyle {\sqrt {a_{1}^{2}+a_{2}^{2}}}{\sqrt {b_{1}^{2}+b_{2}^{2}}}\sin {\left[\arccos {\left(a_{1}b_{1}+a_{2}b_{2}\right)}\right]}} NightKhaos (talk) 21:58, 30 March 2009 (UTC)