I've joked about this twice already, but I really need it. Just using bookmarks doesn't hack it for me, so here goes.
I've just noticed Mozilla keywords... http://www.wikipedia.org/w/wiki.phtml?search=%s&go=Go works well for those links on the mailing list.
m / ( 1 − β 2 ) 2 3 {\displaystyle {\it {{m}/(1-\beta ^{2})_{2}^{3}}}}
m / ( 1 − β 2 ) 1 2 {\displaystyle {\it {{m}/(1-\beta ^{2}){\frac {1}{2}}}}}
2 3 e 2 / a {\displaystyle \ _{2}^{3}e^{2}/{\it {a}}}
For this page on Distributed Proofreaders:
( a b ) 2 = a b × a b = a 2 b 2 {\displaystyle \left({\frac {a}{b}}\right)^{2}={\frac {a}{b}}\times {\frac {a}{b}}={\frac {a^{2}}{b^{2}}}}
( m n + 1 x ) ( m n − 1 x ) = m 2 n 2 − 1 x 2 {\displaystyle \left({\frac {m}{n}}+{\frac {1}{x}}\right)\left({\frac {m}{n}}-{\frac {1}{x}}\right)={\frac {m^{2}}{n^{2}}}-{\frac {1}{x^{2}}}}
( x y − 3 ) ( x y − 6 ) = x 2 y 2 − 9 x y + 18 {\displaystyle \left({\frac {x}{y}}-3\right)\left({\frac {x}{y}}-6\right)={\frac {x^{2}}{y^{2}}}-{\frac {9x}{y}}+18}
b 4 a 4 − y 4 x 4 = ( b 2 a 2 + y 2 x 2 ) ( b a + y x ) ( b a − y x ) {\displaystyle {\frac {b^{4}}{a^{4}}}-{\frac {y^{4}}{x^{4}}}=\left({\frac {b^{2}}{a^{2}}}+{\frac {y^{2}}{x^{2}}}\right)\left({\frac {b}{a}}+{\frac {y}{x}}\right)\left({\frac {b}{a}}-{\frac {y}{x}}\right)}
x 4 + x 2 + 1 4 = ( x 2 + 1 2 ) 2 {\displaystyle x^{4}+x^{2}+{\frac {1}{4}}=\left(x^{2}+{\frac {1}{2}}\right)^{2}}
( 2 x 2 a b 3 ) 2 {\displaystyle \left({\frac {2x^{2}}{ab^{3}}}\right)^{2}}
( a 2 b 3 4 y ) 3 {\displaystyle \left({\frac {a^{2}b^{3}}{4y}}\right)^{3}}
( x ( a − b ) 3 a 2 b ) 4 {\displaystyle \left({\frac {x(a-b)}{3a^{2}b}}\right)^{4}}
( − 5 x 2 y ( a + b 2 ) 2 2 a b 3 ( x 2 − y ) 3 ) 3 {\displaystyle \left(-{\frac {5x^{2}y(a+b^{2})^{2}}{2ab^{3}(x^{2}-y)^{3}}}\right)^{3}}
( − 3 a m 4 ( 2 a + 3 b ) 3 4 x 2 y 2 ( m − n ) 2 ) 3 {\displaystyle \left(-{\frac {3am^{4}(2a+3b)^{3}}{4x^{2}y^{2}(m-n)^{2}}}\right)^{3}}
For this page:
{ 3 x 5 − 2 y 7 = 35 , x + 2 y = − 63. {\displaystyle \left\{{\begin{matrix}{\frac {3x}{5}}-{\frac {2y}{7}}=35,\\x+2y=-63.\end{matrix}}\right.}
{ x − 3 y 5 = 6 , 2 x 3 + 7 y = 189. {\displaystyle \left\{{\begin{matrix}x-{\frac {3y}{5}}=6,\\{\frac {2x}{3}}+7y=189.\end{matrix}}\right.}
{ x + 2 y 3 x − y = 1 , 4 y − x 3 + x − 2 y = 2 1 2 . {\displaystyle \left\{{\begin{matrix}{x+2y \over 3x-y}=1,\\{4y-x \over 3+x-2y}=2{\frac {1}{2}}.\end{matrix}}\right.}
{ x + 2 y x − 2 = − 5 2 3 , 2 y − 4 x 3 − y = − 6. {\displaystyle \left\{{\begin{matrix}{x+2y \over x-2}=-5{\frac {2}{3}},\\{2y-4x \over 3-y}=-6.\end{matrix}}\right.}
{ y − 2 y + x 3 = 2 x + y 4 − 8 3 4 , 3 x + y 2 − y 3 = 109 10 + 4 y − x 5 . {\displaystyle \left\{{\begin{matrix}y-{\frac {2y+x}{3}}={\frac {2x+y}{4}}-8{\frac {3}{4}},\\{\frac {3x+y}{2}}-{\frac {y}{3}}={\frac {109}{10}}+{\frac {4y-x}{5}}.\end{matrix}}\right.}
{ 3 x − 19 2 + 4 = 3 y + x 3 + 5 x − 3 2 , 4 x + 5 y 16 + 2 x + y 2 = 9 x − 7 8 + 3 y + 9 4 . {\displaystyle \left\{{\begin{matrix}{\frac {3x-19}{2}}+4={\frac {3y+x}{3}}+{\frac {5x-3}{2}},\\{\frac {4x+5y}{16}}+{\frac {2x+y}{2}}={\frac {9x-7}{8}}+{\frac {3y+9}{4}}.\end{matrix}}\right.}
{ 1 5 ( 3 x − 2 y ) + 1 3 ( 5 x − 3 y ) = x , 4 x − 3 y 2 + 2 3 x − y = 1 + y . {\displaystyle \left\{{\begin{matrix}{\frac {1}{5}}(3x-2y)+{\frac {1}{3}}(5x-3y)=x,\\{\frac {4x-3y}{2}}+{\frac {2}{3}}x-y=1+y.\end{matrix}}\right.}
[1]
x 3 + 2 x 2 + 3 x 3 x 2 − 2 x + 1 _ 3 x 5 + 6 x 4 + 9 x 3 − 2 x 4 − 4 x 3 − 6 x 2 x 3 + 2 x 2 + 3 x _ 3 x 5 + 4 x 4 + 6 x 3 − 4 x 2 + 3 x {\displaystyle {\begin{matrix}x^{3}+2x^{2}+3x\\{\underline {3x^{2}-2x+1}}\\3x^{5}+6x^{4}+9x^{3}\\\qquad \qquad \quad -2x^{4}-4x^{3}-6x^{2}\\{\underline {\qquad \qquad \qquad \qquad \qquad x^{3}+2x^{2}+3x}}\\3x^{5}+4x^{4}+6x^{3}-4x^{2}+3x\end{matrix}}}
5 6 a 4 − 1 5 a 3 b − 1 3 a 2 b 2 by 6 5 a b 2 . {\displaystyle {\frac {5}{6}}a^{4}-{\frac {1}{5}}a^{3}b-{\frac {1}{3}}a^{2}b^{2}{\mbox{by}}{\frac {6}{5}}ab^{2}.}
![[1]](http://www.pgdp.net/projects/projectID3f122c6469863/055.png){kind=link}