${\pi }_{5}$

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$\sum _{k=1}^{\infty }{\frac {1}{x^{k}}}={\frac {1}{x-1}},x>1$

It subsequently follows that

$\sum _{k=0}^{\infty }{\frac {1}{x^{k}}}=1+{\frac {1}{x-1}},x>1$

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User:Hotdogjuicer edit

$log_{5}{\sqrt[{e}]{\pi ^{\pi }}}+\sum _{k={\sqrt {2}}}^{\infty }{\frac {\pi }{k!}}+\prod _{k={\sqrt[{\pi }]{529}}}^{\infty }log_{k}{\sqrt[{k}]{426_{k}}}=\lim _{n\to \infty }(n+{\sqrt[{n}]{n}})^{\infty }$

$\triangle \Delta \square$

just experimenting with symbols

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user:hotdogjuicer

H E L L O T H E R E

More Symbols edit

This is school-related ${{\sqrt {{X^{2}-2X+1} \over {X+2{\sqrt {X}}+1}}}+{{X^{3}+3X^{2}+3X+1} \over {X^{2}+2X+1}}} \over {{\sqrt {{X^{3}-X} \over {X^{2}-X}}}+{{X-2{\sqrt {2X}}+1} \over {-({\sqrt {X}}-{\sqrt {2}})^{2}}}}$

Also, I have a hidden page somewhere on here. Your job is to find the link to it.
(the page will have the name "secret page" or something like that at the top)

Hotdogjuicer

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User:Hotdogjuicer edit