1944 United States presidential election in Delaware
(Redirected from United States presidential election in Delaware, 1944)
The 1944 United States presidential election in Delaware took place on November 7, 1944, as part of the 1944 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
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All 3 Delaware votes to the Electoral College | ||||||||||||||||||||||||||
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County Results
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Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Senator Harry S. Truman, with 54.38% of the popular vote, against Governor Thomas E. Dewey (R–New York), running with Governor John W. Bricker, with 45.27% of the popular vote.[3][4]
Results edit
Party | Candidate | Votes | % | |
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Democratic | Franklin D. Roosevelt (inc.) | 68,166 | 54.38% | |
Republican | Thomas E. Dewey | 56,747 | 45.27% | |
Write-in | 448 | 0.36% | ||
Total votes | 125,361 | 100.00% |
Results by County edit
County | Roosevelt | Dewey | Other candidates |
Kent | 7,900 | 7,069 | 57 |
New Castle | 49,588 | 37,783 | 318 |
Sussex | 10,678 | 11,895 | 73 |
Statewide | 68,166 | 56,747 | 448 |
See also edit
References edit
- ^ "United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 26, 2017.
- ^ "1944 Election for the Fortieth Term (1945-49)". Retrieved December 26, 2017.
- ^ "1944 Presidential General Election Results - Delaware". Retrieved December 26, 2017.
- ^ "The American Presidency Project - Election of 1944". Retrieved December 26, 2017.