Talk:Sodium bis(2-methoxyethoxy)aluminium hydride

Latest comment: 7 years ago by Smokefoot in topic Page re-work (and images)

Why is Red-Al named as "red"?

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Red-Al is a colorless solid. Why are it named as "red"?--Wolfch (talk) 04:09, 28 August 2010 (UTC)Reply

Page re-work (and images)

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This page has had a flurry of edits by @Milos831019:, with both the ‘chembox’ and ‘reactions’ images being replaced. Both of the new images have errors:

Also, this compound has several trade names, I find it odd that only Synhydrid is now prominently mentioned. Project Osprey (talk) 13:55, 14 October 2014 (UTC)Reply

Agree that the big scheme should be redrawn with something other than "SDMA" at the center! It is preferable not to have arrows to the substrate but simply a line. About the placement of the negative charge I dont have any good ideas. That aspect does not bother me much. --Smokefoot (talk) 17:40, 14 October 2014 (UTC)Reply
(I converted the image-names to links so we can easily see what we're talking about.) The aluminium is correctly a –1 formal charge in the skeletal-diagram. Looks like File:Reduction_scheme.PNG has been replaced and deleted. The editor in question had replaced it with File:Diagram of SDMA reductions.PNG, but I reverted back to File:Red-Al Reductions.png that had long been there because what-the-hell-is-"SDMA"?. DMacks (talk) 21:08, 14 October 2014 (UTC)Reply

A major difference to LiAlH4 is the reaction towards nitriles, they selectively are reduced to aldehydes (rework image); aromatic aldehydes are reduced to the methyl-group (acros organics brochure: "Aluminiumhydrides and Borohydrides", p.26, ref. is missing). Anna Bolaine (talk) 12:32, 3 April 2017 (UTC)Reply

Thanks for checking, but I think the figure is ok. eEROS is probably a definitive source and as expected the reduction of nitriles depends crtically on conditions:

1) "Nitriles ... can be reduced to the amine." (LAH like.). 2) "Carboxylic esters, nitriles, and amides can be reduced to the aldehyde at low temperatures." (iminate or imine formation, requires hydrolysis to switch out C=N to C=O). Please keep checking because we do not want mistakes.--Smokefoot (talk) 14:10, 3 April 2017 (UTC)Reply