Indian Grove Township is located in Livingston County, Illinois. As of the 2010 census, its population was 4,297 and it contained 1,814 housing units.[2] Indian Grove Township changed its name from Worth Township on May 11, 1858.
Indian Grove Township | |
|---|---|
Township | |
 Location in Livingston County | |
 Livingston County's location in Illinois | |
| Country | United States |
| State | Illinois |
| County | Livingston |
| Established | November 3, 1857 |
| Area | |
| • Total | 36.33 sq mi (94.1 km2) |
| • Land | 36.1 sq mi (93 km2) |
| • Water | 0.23 sq mi (0.6 km2) 0.63% |
| Population (2010) | |
| • Estimate (2016)[1] | 4,104 |
| • Density | 119/sq mi (46/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 17-105-37244 |
Geography edit
According to the 2010 census, the township has a total area of 36.33 square miles (94.1 km2), of which 36.1 square miles (93 km2) (or 99.37%) is land and 0.23 square miles (0.60 km2) (or 0.63%) is water.[2]
Demographics edit
| Census | Pop. | Note | %± |
|---|---|---|---|
| 2016 (est.) | 4,104 | [1] | |
| U.S. Decennial Census[3] | |||
References edit
- ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
- ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
External links edit
40°43′02″N 88°31′45″W / 40.71722°N 88.52917°W
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