2006 BCR Open Romania – Doubles

The Men’s Doubles tournament of the 2006 BCR Open Romania tennis championship took place in Bucharest, Romania, between 11 and 17 September 2006. 16 pairs from 13 countries competed in the 4-round tournament.

Doubles
2006 BCR Open Romania
Final
ChampionsPoland Mariusz Fyrstenberg
Poland Marcin Matkowski
Runners-upArgentina Martín García
Peru Luis Horna
Score6–7(5–7), 7–6(7–5), [10–8]
Details
Draw16 (2WC)
Seeds4
Events
Singles Doubles
← 2005 · Romanian Open · 2007 →

José Acasuso and Sebastián Prieto were the defending champions, but Acasuso opted to rest in order to compete at the Davis Cup the following week. Prieto teamed up with František Čermák and lost in the quarterfinals to Martín García and Luis Horna.

Mariusz Fyrstenberg and Marcin Matkowski won the title by defeating García and Horna 6–7(5–7), 7–6(7–5), [10–8] in the final.[1]

Seeds edit

Draw edit

Key edit

Draw edit

First round Quarterfinals Semifinals Final
1   M Fyrstenberg
  M Matkowski
6 6
  F Serra
  G Simon
3 1 1   M Fyrstenberg
  M Matkowski
6 6
  S Greul
  B Pašanski
1 2   M Mertiňák
  P Pála
2 0
  M Mertiňák
  P Pála
6 6 1   M Fyrstenberg
  M Matkowski
6 6
4   M Kohlmann
  A Waske
6 6   PH Mathieu
  C Rochus
1 2
  J Mónaco
  M Zabaleta
4 4 4   M Kohlmann
  A Waske
69 4
  PH Mathieu
  C Rochus
6 7   PH Mathieu
  C Rochus
711 6
  A di Mauro
  F Volandri
0 5 1   M Fyrstenberg
  M Matkowski
65 77 [10]
  M García
  L Horna
7 6   M García
  L Horna
77 65 [8]
WC   A Pavel
  H Tecău
5 3   M García
  L Horna
3 6 [10]
  G García López
  C Kas
6 66 [3] 3   F Čermák
  S Prieto
6 3 [4]
3   F Čermák
  S Prieto
4 78 [10]   M García
  L Horna
6 6
WC   V Crivoi
  V Ioniță
5 2 2   J Knowle
  J Melzer
2 0
  L Azzaro
  S Roitman
7 6   L Azzaro
  S Roitman
5 5
  R Ramírez Hidalgo
  M Vassallo Argüello
2 3 2   J Knowle
  J Melzer
7 7
2   J Knowle
  J Melzer
6 6

References edit

  1. ^ "ATP Bucharest Doubles 2006 Results". Tennis 24. Retrieved 22 February 2023.

External links edit