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1996 United States presidential election in Alaska

The 1996 United States presidential election in Alaska took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose representatives, or electors to the Electoral College, who voted for president and vice president.

1996 United States presidential election in Alaska

← 1992 November 5, 1996 2000 →
  Bob Dole, PCCWW photo portrait.JPG Bill Clinton.jpg RossPerotColor.jpg
Nominee Bob Dole Bill Clinton Ross Perot
Party Republican Democratic Reform
Home state Kansas Arkansas Texas
Running mate Jack Kemp Al Gore Pat Choate
Electoral vote 3 0 0
Popular vote 122,746 80,380 26,333
Percentage 50.80% 33.27% 10.90%

AK1988(2).jpg
Borough Results
  Dole—50-60%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

Alaska was won by Senator Bob Dole (R-KS), with Dole winning 50.80% to 33.27% over President Bill Clinton (D) by a margin of 17.53%.[1] Billionaire businessman Ross Perot (Reform-TX) finished in third, with 10.9% of the popular vote.

With 50.8% of the popular vote, Alaska proved to be Dole's fifth strongest state in the 1996 election after Utah, Kansas, Nebraska and Idaho.[2]

ResultsEdit

1996 United States presidential election in Alaska
Party Candidate Running mate Votes Percentage Electoral votes
Republican Robert Dole Jack Kemp 122,746 50.80% 3
Democratic Bill Clinton (incumbent) Al Gore 80,380 33.27% 0
Reform Ross Perot Patrick Choate 26,333 10.90% 0
Green Party Ralph Nader Winona LaDuke 7,597 3.14% 0
Libertarian Harry Browne Jo Jorgensen 2,276 0.94% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 925 0.38% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 729 0.30% 0
Write-ins 634 0.26% 0
Totals 241,620 100.0% 3

ReferencesEdit

  1. ^ Dave Leip's Atlas of United States Presidential Election Results - 1996 Alaska Results
  2. ^ "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.