1940 Iowa gubernatorial election

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

1940 Iowa gubernatorial election

← 1938 November 7, 1940 1942 →
 
Nominee George A. Wilson John K. Valentine
Party Republican Democratic
Popular vote 620,480 553,941
Percentage 52.72% 47.07%

County results
Wilson:      40–50%      50–60%      60–70%
Valentine:      50–60%

Governor before election

George A. Wilson
Republican

Elected Governor

George A. Wilson
Republican

Primary elections

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Primary elections were held on June 3, 1940.[1]

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic John K. Valentine 70,233 57.88
Democratic Edward Breen 51,112 42.12
Total votes 121,345 100.00

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican George A. Wilson (incumbent) 165,176 49.66
Republican H. R. Gross 146,395 44.01
Republican Irving H. Knudson 21,039 6.33
Total votes 332,610 100.00

General election

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Candidates

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Major party candidates

  • George A. Wilson, Republican
  • John K. Valentine, Democratic

Other candidates

  • M. M. Heptonstall, Prohibition
  • Charles Speck, Communist

Results

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1940 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican George A. Wilson (incumbent) 620,480 52.72%
Democratic John K. Valentine 553,941 47.07%
Prohibition M. M. Heptonstall 1,289 0.11%
Communist Charles Speck 1,230 0.11%
Majority 66,539
Turnout
Republican hold Swing

References

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  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.