1916 United States Senate election in Wyoming

The 1916 United States Senate election in Wyoming took place on November 7, 1916. Incumbent Senator Clarence D. Clark, a Republican, sought re-election in his first popular election. He was opposed by John B. Kendrick, the incumbent Governor of Wyoming and the Democratic nominee. Owing in part to President Woodrow Wilson's strong performance in the presidential election that year, Kendrick won a narrow but decisive victory over Clark, winning the first of three terms in the U.S. Senate.

1916 United States Senate election in Wyoming

← 1911 November 7, 1916 1922 →
  KENDRICK, JOHN B. GOVERNOR LCCN2016859134 (cropped).jpg Senator Clarence Don Clark3.jpg
Nominee John B. Kendrick Clarence D. Clark
Party Democratic Republican
Popular vote 26,324 23,258
Percentage 51.47% 45.47%

U.S. senator before election

Clarence D. Clark
Republican

Elected U.S. Senator

John B. Kendrick
Democratic

Democratic PrimaryEdit

CandidatesEdit

ResultsEdit

Democratic primary[1]
Party Candidate Votes %
Democratic John B. Kendrick 2,877 100.00%
Total votes 2,877 100.00%

Republican PrimaryEdit

CandidatesEdit

ResultsEdit

Republican primary[1]
Party Candidate Votes %
Republican Clarence D. Clark (inc.) 14,045 100.00%
Total votes 14,045 100.00%

General electionEdit

ResultsEdit

1916 United States Senate election in Wyoming[1]
Party Candidate Votes %
Democratic John B. Kendrick 26,324 51.47%
Republican Clarence D. Clark (inc.) 23,258 45.47%
Socialist Paul L. Paulsen 1,334 2.61%
Progressive Arthur B. Campbell 231 0.45%
Total votes 51,147 100.00%
Democratic gain from Republican

ReferencesEdit

  1. ^ a b c Erwin, Marie (1974). Trenholm, Virginia Cole (ed.). Wyoming Blue Book (PDF). Vol. 2. Cheyenne, Wyo.: Pioneer Printing & Stationery Co. pp. 589–90.