1899 Iowa gubernatorial election

The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

1899 Iowa gubernatorial election

← 1897 November 7, 1899 1901 →
 
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 239,464 183,301
Percentage 55.26% 42.30%

County results
Shaw:      40-50%      50-60%      60-70%      70-80%
White:      40-50%      50-60%

Governor before election

L. M. Shaw
Republican

Elected Governor

L. M. Shaw
Republican

General election

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Candidates

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Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • Marshall W. Atwood, Prohibition
  • Charles Lloyd, People's
  • M. J. Kremer, Socialist Labor
  • C. C. Heacock, United Christian

Results

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1899 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican L. M. Shaw (incumbent) 239,464 55.26%
Democratic Frederick Edward White 183,301 42.30%
Prohibition Marshall W. Atwood 7,639 1.76%
Populist Charles Lloyd 1,698 0.39%
Socialist Labor M. J. Kremer 757 0.18%
Independent C. C. Heacock 484 0.11%
Majority 56,163
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 7, 2020.