1898 Minnesota Senate election

The 1898 Minnesota Senate election was held in the U.S. state of Minnesota on November 8, 1898, to elect members to the Senate of the 31st and 32nd Minnesota Legislatures.

1898 Minnesota Senate election

← 1894 November 8, 1898 (1898-11-08) 1902 →

All 63 seats in the Minnesota Senate
32 seats needed for a majority
  Majority party Minority party
 
GOP
DEM
Party Republican Democratic
Seats won 44 17
Seat change Decrease2 Increase14
Popular vote 136,070 92,740
Percentage 57.8% 39.4%

MNSen1898.svg

On the coattails of Democrat John Lind's gubernatorial campaign, the Minnesota Democratic Party saw a minor resurgence in the Senate. The Party consolidated much of the third party support that had become a large factor in the elections of 1890 and 1894. The People's Party endorsed a handful of Democratic candidates that ended up winning and caucusing as Democrats in the Senate.

The Minnesota Republican Party won a large majority of seats followed by the Minnesota Democratic Party. The new Legislature convened on January 3, 1899.

Two independent candidates won election to the Senate, one of whom caucused with Democrats upon being seated. In the 48th District, two Republicans ran against one another, and the winner was the one who had not been endorsed by the Party. Both candidates are listed as Republicans in the vote aggregate.[1]

ResultsEdit

Summary of the November 8, 1898 Minnesota Senate election results
Party Candidates Votes Seats
No. %
Republican Party 64 136,070 44 57.82
Democratic Party 54 92,740 17 39.41
Independent 14 6,530 2 2.77
Total 235,340 63 100.00
Source: Minnesota Secretary of State[2]

*These totals count candidates endorsed by the Democratic and People's Parties in the totals for the Democratic Party.

See alsoEdit

ReferencesEdit

  1. ^ 1899 Minnesota Legislative Manual. Minnesota Secretary of State. 1899. pp. 509–517.
  2. ^ "Election Results - Minnesota Legislative Reference Library". www.leg.state.mn.us. Retrieved 2020-01-08.