The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.
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General election edit
Candidates edit
Major party candidates
- Hiram A. Tuttle, Republican
- Charles H. Amsden, Democratic
Other candidates
- Josiah M. Fletcher, Prohibition
Results edit
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Hiram A. Tuttle | 42,479 | 49.26% | ||
| Democratic | Charles H. Amsden | 42,386 | 49.15% | ||
| Prohibition | Josiah M. Fletcher | 1,343 | 1.56% | ||
| Majority | 93 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References edit
- ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.