1889 Chicago mayoral election

In the Chicago mayoral election of 1889, Democrat DeWitt Clinton Cregier defeated incumbent Republican John A. Roche, winning a majority of the vote and a margin of victory in excess of ten percent.

1889 Chicago mayoral election
← 1887 April 2, 1889 1891 →
 
Nominee DeWitt Clinton Cregier John A. Roche
Party Democratic Republican
Popular vote 57,340 46,328
Percentage 54.93% 44.38%

Mayor before election

John A. Roche
Republican

Elected Mayor

DeWitt Clinton Cregier
Democratic

The election was held on April 2, 1889.[1][2]

Campaign edit

Cregier backed strongly by trade unions.[3] John Peter Altgeld threw his backing behind Cregier's candidacy.[3]

Results edit

1889 Chicago mayoral election[1]
Party Candidate Votes %
Democratic DeWitt Clinton Cregier 57,340 54.93
Republican John A. Roche (incumbent) 46,328 44.38
Prohibition Ira J. Mason 410 0.39
Socialist Charles Orchardson 303 0.29
Turnout 104,381

Creiger received 76.86% of the Polish-American vote, while Roche received 23.07%.[4]

References edit

  1. ^ a b The Chicago Daily News Almanac and Year Book for 1912. Chicago Daily News, Incorporated. 1911. p. 464. Retrieved May 12, 2020.
  2. ^ Currey, Josiah Seymour (1912). Chicago: Its History and Its Builders, a Century of Marvelous Growth. S. J. Clarke publishing Company. p. 335.
  3. ^ a b Kersten, Andrew E. (2011). Clarence Darrow: American Iconoclast. Macmillan. p. 46. ISBN 978-0-8090-9486-8. Retrieved June 2, 2020.
  4. ^ Kantowicz, Edward (1972). "The Emergence of the Polish-Democratic Vote in Chicago". Polish American Studies. 29 (1/2): 67–80. JSTOR 20147849.