1887 Iowa gubernatorial election

The 1887 Iowa gubernatorial election was held on Tuesday November 8, 1887. Incumbent Republican William Larrabee defeated Democratic nominee Thomas J. Anderson with 50.18% of the vote.

1887 Iowa gubernatorial election

← 1885 November 8, 1887 1889 →
 
Nominee William Larrabee Thomas J. Anderson
Party Republican Democratic
Popular vote 169,596 153,706
Percentage 50.18% 45.47%

County results
Larrabee:      40-50%      50-60%      60-70%      70-80%      80-90%
Anderson:      40-50%      50-60%      60-70%      70-80%

Governor before election

William Larrabee
Republican

Elected Governor

William Larrabee
Republican

General election

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Candidates

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Major party candidates

  • William Larrabee, Republican
  • Thomas J. Anderson, Democratic

Other candidates

  • M. J. Cain, Union Labor
  • V. G. Farnham, Prohibition

Results

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1887 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William Larrabee (incumbent) 169,596 50.18%
Democratic Thomas J. Anderson 153,706 45.47%
Labor M. J. Cain 14,283 4.23%
Prohibition V. G. Farnham 334 0.10%
Majority 15,890
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 14, 2020.