1877 Iowa gubernatorial election

The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.

1877 Iowa gubernatorial election

← 1875 October 9, 1877 1879 →
 
Nominee John H. Gear John P. Irish Daniel P. Stubbs
Party Republican Democratic Greenback
Popular vote 121,316 79,304 34,316
Percentage 49.39% 32.29% 13.97%

County results
Gear:      30-40%      40-50%      50-60%      60-70%      70-80%      80-90%      90-100%
Irish:      30-40%      40-50%      50-60%      60-70%
Stubbs:      50-60%

Governor before election

Joshua G. Newbold
Republican

Elected Governor

John H. Gear
Republican

General election

edit

Candidates

edit

Major party candidates

  • John H. Gear, Republican
  • John P. Irish, Democratic

Other candidates

  • Daniel P. Stubbs, Greenback
  • Elias Jessup, Prohibition

Results

edit
1877 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican John H. Gear 121,316 49.39%
Democratic John P. Irish 79,304 32.29%
Greenback Daniel P. Stubbs 34,316 13.97%
Prohibition Elias Jessup 10,565 4.30%
Majority 42,012
Turnout
Republican hold Swing

References

edit
  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved September 21, 2020.