The 1860 United States presidential election in Wisconsin was held on November 6, 1860, as part of the 1860 United States presidential election. State voters chose five electors to the Electoral College, who voted for president and vice president.
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County Results
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Wisconsin was won by the Republican Party candidate Abraham Lincoln and his running mate Hannibal Hamlin. They defeated the Democratic Party candidate Stephen A. Douglas and his running mate Herschel V. Johnson. Lincoln won the state by a margin of 13.86%.
Results
edit1860 United States presidential election in Wisconsin[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 86,113 | 56.59% | 5 | 100.00% | ||
Democratic | Stephen Arnold Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 65,021 | 42.73% | 0 | 0.00% | ||
Southern Democratic | John Cabell Brekinridge of Kentucky | Joseph Lane of Oregon | 888 | 0.58% | 0 | 0.00% | ||
Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 161 | 0.11% | 0 | 0.00% | ||
Total | 152,183 | 100.00% | 5 | 100.00% |