1860 United States presidential election in Massachusetts
The 1860 United States presidential election in Massachusetts took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose 13 electors of the Electoral College, who voted for president and vice president.
|Turnout||65.8% 4.0 pp|
|1860 United States presidential election in Massachusetts|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||Abraham Lincoln of Illinois||Hannibal Hamlin of Maine||106,684||62.80%||13||100.00%|
|Democratic||Stephen A. Douglas of Illinois||Herschel Vespasian Johnson of Georgia||34,370||20.23%||0||0.00%|
|Constitutional Union||John Bell of Tennessee||Edward Everett of Massachusetts||22,331||13.15%||0||0.00%|
|Southern Democratic||John C. Breckinridge of Kentucky||Joseph Lane of Oregon||6,163||3.63%||0||0.00%|
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1860 Presidential General Election Results - Massachusetts".
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