1836 United States presidential election in Missouri

The 1836 United States presidential election in Missouri took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Missouri

← 1832 November 3 – December 7, 1836 1840 →
  Martin Van Buren circa 1837 crop.jpg HLWhite.jpg
Nominee Martin Van Buren Hugh White
Party Democratic Whig
Home state New York Tennessee
Running mate Richard Johnson John Tyler
Electoral vote 4 0
Popular vote 10,995 7,337
Percentage 59.98% 40.02%

Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Missouri by a margin of 19.96%.

ResultsEdit

1836 United States presidential election in Missouri[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 10,995 59.98% 4
Whig Hugh White 7,337 40.02% 0
Totals 18,332 100.0% 4

See alsoEdit

ReferencesEdit

  1. ^ "1836 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 15 April 2013.